Regex, Removing Recurring Characters But Keeping At Least One December 14, 2023 Post a Comment I'm using this html = html.replace(/([^0-9]).*?\1/ , ''); but it's not quite doing what I'm trying to do. I want to replace the doubles within a string, but still keep at least oSolution 1: THink you mean this,str.replace(/(.)\1+/g, '$1') Copyor str.replace(/([^0-9])\1+/g, '$1') CopyBaca JugaAmend Javascript To Also Remove StringWrap/break List Items In Two UlJavascript Replace Undefined Error Shows! Share You may like these postsParenthesis Not Being Replaced In RegexHow To Replace All Undefined Values In An Array With "-"?Regex: String Match Including PunctuationReplacing Letters In A String Using Two Arrays? Post a Comment for "Regex, Removing Recurring Characters But Keeping At Least One"
/g,'img src='smiley.gif'')</div>
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